Active 5 years, 6 months ago. Viewed 7k times. Why is that? I would assume that the total charge should just evenly spread between the spheres. Improve this question. Quantaliinuxite Quantaliinuxite 1 1 silver badge 5 5 bronze badges. Add a comment. Active Oldest Votes. Improve this answer. Farcher Farcher Sreekar Voleti Sreekar Voleti 5 5 silver badges 19 19 bronze badges. What if the inner sphere is never connected to the outer sphere? By your first sentence we must conclude that E between the spheres is 0, but it's not.
Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. Featured on Meta. Now live: A fully responsive profile. Linked 0. Related 1. Hot Network Questions. Thus, there are more charges per unit area on the smaller sphere than the bigger sphere. We can generalize this model to describe charges on any charged conducting object. Instead, there will be a higher charge density charges per unit area , near parts of the object that have a small radius of curvature sharp points on the object in particular , just as the charge density was higher on the smaller sphere described above.
The strong electric field can remove electron from atoms in the air, ionizing the air in a chain reaction and making it conductive. Thus, if the electric field at a point on the surface of a conductor is very strong, the air near that point will break down, and charges will leave the conductor, through the air, to find a location with lower electric potential energy usually the ground.
Electric breakdown is what we experience as a spark or lightning, on a larger scale , and is usually a discrete and potentially dramatic event. Corona discharge is another mechanism whereby the strong electric field can make the air conductive, but in this case charges leak into the air more gradually, unlike in the case of electrical break down.
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